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NEET MCQ
NEET 2020 Physics Memory Based
Q. A proton is accelerating in a cyclotron where the applied magnetic field is 2 T. If the potential gap is effectively 100 kV then how many revolutions the proton has to make to acquire a kinetic energy of 20 MeV?
  • A) 100
  • B) 150
  • C) 200
  • D) 300

Solution:

Energy gained per revolution = 2 × 100 × 103 eV
= 2 × 105 eV

Required energy = 20 MeV = 2 × 107 eV

Number of revolutions =
(2 × 107) / (2 × 105) = 100

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